## T4 Cosine rule

Pythagoras’s Theorem may be used to find the third side in any right angled triangle. The Cosine Rule can be used to solve non-right triangles.

### The Cosine Rule

Consider the triangle below:

The angles A, B, C are the angles at the vertices A, B, C respectively. The sides a, b, and c are opposite angles A, B, C respectively.

The Cosine Rule states:

\begin{align*} a^{2} & =b^{2}+c^{2}-2bc\cos A\\ b^{2} & =a^{2}+c^{2}-2ac\cos B\\ c^{2} & =a^{2}+b^{2}-2ab\cos C. \end{align*}

Note that the side on the left hand side of the equation is opposite the angle listed at the end of the equation:

\begin{align*} \boldsymbol{\underline{a^{2}}} & =b^{2}+c^{2}-2bc\,\cos\boldsymbol{\underline{A}}. \end{align*}

Use the Cosine Rule when you are given:

1. two sides and the angle between them, or

2. all three sides of the triangle.

#### Examples

1. Find the value of $$a$$ in this triangle

\begin{align*} a^{2} & =b^{2}+c^{2}-2bc\,\cos A\\ a^{2} & =12^{2}+15^{2}-2\times12\times15\times\cos83^{\circ}\\ a^{2} & =144+225-360\times\cos83^{\circ}\\ a^{2} & =369-43.87\\ a^{2} & =325.13\\ a & =18.03 \end{align*}

1. Find the size of angle B in this triangle:

\begin{align*} b^{2} & =a^{2}+c^{2}-2ac\,\cos B\\ 11^{2} & =5^{2}+7^{2}-2\times5\times7\times\cos B\\ 121 & =25+49-70\times\cos B\\ 121-25-49 & =-70\times\cos B\\ 47 & =-70\times\cos B\\ \frac{47}{-70} & =\cos B\\ B & =\cos^{-1}\left(-\frac{47}{70}\right)\\ B & =132^{\circ}11^{\prime} \end{align*}

### Exercise

1. Use the sine OR cosine rule to find the pro-numeral shown:

c)

1. Find the magnitude of the labeled, unknown angle

1 a) $$28.7\quad$$ b) $$4.38\quad$$ c) $$8.33\quad$$d) $$1.05$$
2 a) $$\alpha=34.2^{\circ}\quad$$ b) $$\beta=42.9^{\circ}.$$